A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids.
The formula of the compound is :
Anions(A) are in hcp, so number of anions (A) = 6
Cations(C) are in 75% O.V., so number of cations (C)
= 6 x 3 /4
= 18 /4
=9 / 2
So formula of compound will be
C 9/2 A 6 => C 9A 12
C 9A 12 => C 3A 4
Anions(A) are in hcp, so number of anions (A) = 6
Cations(C) are in 75% O.V., so number of cations (C)
= 6 x 3 /4
= 18 /4
=9 / 2
So formula of compound will be
C 9/2 A 6 => C 9A 12
C 9A 12 => C 3A 4